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$80 \mathrm{~g}$ of oxygen contains as many atoms as in
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$5 \mathrm{~g}$ of hydrogen
Number of atoms $=\frac{\text { mass }}{\text { molecular mass }} \times N_{A}$
Number of atoms is oxygen $=$ product of atoms in hydrogen
$\frac{80}{16} \times N_{A}=\frac{W}{1} \times N_{A}$
$\therefore \quad W=\frac{80}{16}=5$ g of hydrogen
Number of atoms is oxygen $=$ product of atoms in hydrogen
$\frac{80}{16} \times N_{A}=\frac{W}{1} \times N_{A}$
$\therefore \quad W=\frac{80}{16}=5$ g of hydrogen
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