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9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of arranging one ball in each of the boxes is
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1528 Upvotes
Verified Answer
The correct answer is:
$17280$
Required number of arrangements
$$
\begin{aligned}
& ={ }^6 P_5 \times 4 ! \\
& =720 \times 24 \\
& =17280
\end{aligned}
$$
$$
\begin{aligned}
& ={ }^6 P_5 \times 4 ! \\
& =720 \times 24 \\
& =17280
\end{aligned}
$$
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