Search any question & find its solution
Question:
Answered & Verified by Expert
${ }_{92}^{238} \mathrm{U}$ has 92 protons and 238 nucleons. It decays by emitting an alpha particle and becomes
Options:
Solution:
1394 Upvotes
Verified Answer
The correct answer is:
${ }_{90}^{234} \mathrm{Th}$
Emission of alpha particle, decrease the mass number by 4 and charge number by 2 .
$\therefore$ Decrease in mass number $=238-4=234$
Decrease in charge number $=92-2=90$ ${ }_{90}^{234} \mathrm{Th}$ is emitted.
$\therefore$ Decrease in mass number $=238-4=234$
Decrease in charge number $=92-2=90$ ${ }_{90}^{234} \mathrm{Th}$ is emitted.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.