A 0.004 M solution of N a 2 S O 4 is isotonic with a 0.010 M solution of glucose at same temperature. The apparent degree of dissociation of N a 2 S O 4 is

Question

A 0.004 M solution of N a 2 S O 4 is isotonic with a 0.010 M solution of glucose at same temperature. The apparent degree of dissociation of N a 2 S O 4 is, 25%, 50%, 75%, 85%

MARKS App · Accepted Answer

P ( N a 2 S O 4 ) = i C R T = i ( 0.004 ) R T P (glucose) = CRT = 0.010 RT As solutions are isotonic, i (0.004) RT = 0.01 RT this gives i = 2.5 N a 2 S O 4 → 2 N a + + S O 4 2 - α = i - 1 n - 1 Here n = 3 α = 2.5 - 1 2 = 1.5 2 = 0.75 = 75 %

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