A 0.2 kg object at rest is subjected to a force 0.3 i ⁡ ^ - 0.4 j ⁡ ^ newton. The velocity vector after 6s is

Question

A 0.2 kg object at rest is subjected to a force 0.3 i ⁡ ^ - 0.4 j ⁡ ^ newton. The velocity vector after 6s is, 9 i ⁡ ^ - 1 2 j ⁡ ^, 8 i ⁡ ^ - 1 6 j ⁡ ^, 1 2 i ⁡ ^ - 9 j ⁡ ^, 1 6 i ⁡ ^ - 8 j ⁡ ^

MARKS App · Accepted Answer

Here, m = 0.2 kg ; u = 0 F → = 0.3 i ^ - 0.4 j ^ N v → = ? , t = 6 s a → = F → m = 0.3 i ^ - 0.4 j ^ 0.2 = 3 2 i ^ - 2 j ^ From v → = u → + a → t , v → = 0 + 3 2 i ^ - 2 j ^ × 6 = 9 i ^ - 1 2 j ^

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