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A $0.3 \mathrm{M~} \mathrm{HCl}$ solution contains the following ions $\mathrm{Hg}^{2+}, \mathrm{Cd}^{2+}, \mathrm{Sr}^{2+}, \mathrm{Fe}^{2+}, \mathrm{Cu}^{2+}$. The addition of $\mathrm{H}_2 \mathrm{~S}$ to above solution will precipitate
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$\mathrm{Cd}, \mathrm{Cu}$ and $\mathrm{Hg}$
The second group radicals will precipitate because their solubility product is very low so sulphates will be precipitated.
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