A $ 0.50 \mathrm{~g} $ mixture of $ \mathrm{Cu}_{2} \mathrm{O} $ and $ \mathrm{CuO} $ contains $ 0.425 \mathrm{~g} $ of $ \mathrm{Cu} $. What is the mass of $ \mathrm{CuO}( $ in $ \mathrm{g}) $ in the mixture? $$ (\mathrm{Cu}=63.5 \mathrm{u}, \mathrm{O}=16 \mathrm{u}) $$ Answer correct up to two places of decimals.

Question

A $ 0.50 \mathrm{~g} $ mixture of $ \mathrm{Cu}_{2} \mathrm{O} $ and $ \mathrm{CuO} $ contains $ 0.425 \mathrm{~g} $ of $ \mathrm{Cu} $. What is the mass of $ \mathrm{CuO}( $ in $ \mathrm{g}) $ in the mixture? $$ (\mathrm{Cu}=63.5 \mathrm{u}, \mathrm{O}=16 \mathrm{u}) $$ Answer correct up to two places of decimals.,

MARKS App · Accepted Answer

Let the mass of CuO = w g For one mole of Cu 2 O : mass of Cu = 127 g ; gram molecular mass = 143 g For one mole of CuO : mass of Cu = 63 . 5 g ; gram molecular mass = 79 . 5 g Thus, for w g CuO , mass of Cu = 63 . 5 w 79 . 5 g And, for 0 . 5 - w g Cu 2 O , mass of Cu = 127 0 . 5 - w 143 g Now, 63 . 5 w 79 . 5 + 127 0 . 5 - w 143 = 0 . 425 w = 0 . 21 g

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