Search any question & find its solution
Question:
Answered & Verified by Expert
A $1 \mathrm{~kg}$ object strikes a wall with velocity $1 \mathrm{~ms}^{-1}$ at an angle of $60^{\circ}$ with the wall and reflects at the same angle. If it remains in contact with wall for $0.1 \mathrm{~s}$, then the force exerted on the wall is
Options:
Solution:
2028 Upvotes
Verified Answer
The correct answer is:
$10 \sqrt{3} \mathrm{~N}$

$\begin{aligned} & F=\frac{\Delta p}{\Delta t} \\ & \Delta p=2 m v \cos 30^{\circ} \\ & =2 \times 1 \times \frac{\sqrt{3}}{2}=\sqrt{3} \\ & F=\frac{\sqrt{3}}{0.1}=10 \sqrt{3} \mathrm{~N}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.