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Question: Answered & Verified by Expert
1 kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed of 4 m s-1. The tension in the string is 6 N when the stone is at (g=10 m s-2)
PhysicsLaws of MotionNEET
Options:
  • A Top of the circle
  • B Bottom of the circle
  • C Half way down
  • D None of the above
Solution:
2362 Upvotes Verified Answer
The correct answer is: Top of the circle
Tension at top point T + mg = mu 2 r

∴    T = 1 × 4 2 1 - 1 × 1 0 = N

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