A 10 μ C charge is divided into two parts and placed at 1 cm distance so that the repulsive force between them is maximum. The charges of the two parts are:

Question

A 10 μ C charge is divided into two parts and placed at 1 cm distance so that the repulsive force between them is maximum. The charges of the two parts are:, 7 μ C , 3 μ C, 8 μ C , 2 μ C, 5 μ C , 5 μ C, 9 μ C , 1 μ C

MARKS App · Accepted Answer

Let the charges be x μC , q - x μC , where q = 10 μC The force between them is F = K x ( q - x ) r 2 . For the force to be maximum, d F d x = 0 ⇒ d F d x = K ( q - 2 x ) r 2 = 0 ⇒ x = q 2 = 5 μC

Search any question & find its solution

Looking for more such questions to practice?