A 10 g mixture of hydrogen and helium is contained in a vessel of capacity 0 . 0125 m 3 at 6 bar and 27 ° C . The mass of helium in the mixture is ..... g . (Given : R = 8 . 3 JK - 1 mol - 1 (Atomic masses of H and He are 1 u and 4 u , respectively)

Question

A 10 g mixture of hydrogen and helium is contained in a vessel of capacity 0 . 0125 m 3 at 6 bar and 27 ° C . The mass of helium in the mixture is ..... g . (Given : R = 8 . 3 JK - 1 mol - 1 (Atomic masses of H and He are 1 u and 4 u , respectively),

MARKS App · Accepted Answer

PV = n mix RT n mix = 6 × 12 . 5 0 . 083 × 300 ≈ 3 Out of total 3 moles Let mole of He = x Mole of H 2 = 3 - x Then total mass of the mixture will be = 4 x + 2 3 - x = 10 Number of moles of He gas x = 2 mol Mass of He = number of moles × molar mass = 8 g

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