A 1.0 M solution of Cd²⁺ is added to excess iron and the system is allowed to reach equilibrium. What is the concentration in mol of Cd²⁺?

${\text{Cd}}^{2+}\left(\text{aq}\right)+\text{Fe}\left(s\right)\to \text{Cd}\left(s\right)+{\text{Fe}}^{2+}\left(\text{aq}\right);{\text{E}}^o=0.037\text{V}$
 
Given: log 18 = 1.25
Report your answer upto two decimal places.