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Question: Answered & Verified by Expert
A 10.0 g sample of a mixture of calcium chloride and sodium chloride is treated with Na2CO3 to precipitate the calcium as calcium carbonate. This CaCO3 is heated to convert all the calcium to CaO and the final mass of CaO is 1.62 gms. The % by mass of CaCl2 in the original mixture is
ChemistrySome Basic Concepts of ChemistryJEE Main
Options:
  • A 15.2%
  • B 32.1%
  • C 21.8%
  • D 11.07%
Solution:
2598 Upvotes Verified Answer
The correct answer is: 32.1%
Moles = Weightingm Molecularweight
Moles of CaO= 1.62 56
Moles of CaCl2=1.6256
Mass of CaCl 2 = 1.62 56 ×111=3.21gm
Mass %= Weightingm Totalweightgiven ×100
% of CaCl2=3.2110×100=32.1%

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