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Question: Answered & Verified by Expert
A \( 100 \mathrm{~W} \) bulb is connected to an \( \mathrm{AC} \) source of \( 220 \mathrm{~V}, 50 \mathrm{~Hz} \). Then the current flowing through
the bulb is
PhysicsAlternating CurrentKCETKCET 2018
Options:
  • A \( \frac{5}{11} A \)
  • B \( \frac{1}{2} A \)
  • C \( 2 \mathrm{~A} \)
  • D \( \frac{3}{4} A \)
Solution:
2591 Upvotes Verified Answer
The correct answer is: \( \frac{5}{11} A \)
Given, power of bulb \( =100 \mathrm{~W} \); voltage of source \( =200 \mathrm{~V} \)
Now, \( P=I V \Rightarrow I=\frac{P}{V}=\frac{100}{220}=\frac{5}{11} A \)
Therefore, current flowing through the bulb is \( \frac{5}{11} A \)

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