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A \( 100 \mathrm{~W} \) bulb is connected to an \( \mathrm{AC} \) source of \( 220 \mathrm{~V}, 50 \mathrm{~Hz} \). Then the current flowing through
the bulb is
Options:
the bulb is
Solution:
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Verified Answer
The correct answer is:
\( \frac{5}{11} A \)
Given, power of bulb \( =100 \mathrm{~W} \); voltage of source \( =200 \mathrm{~V} \)
Now, \( P=I V \Rightarrow I=\frac{P}{V}=\frac{100}{220}=\frac{5}{11} A \)
Therefore, current flowing through the bulb is \( \frac{5}{11} A \)
Now, \( P=I V \Rightarrow I=\frac{P}{V}=\frac{100}{220}=\frac{5}{11} A \)
Therefore, current flowing through the bulb is \( \frac{5}{11} A \)
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