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A $120 \mathrm{~m}$ long train is moving in a direction with speed $20 \mathrm{~m} / \mathrm{s}$. A train $B$ moving with $30 \mathrm{~m} / \mathrm{s}$ in the opposite direction and $130 \mathrm{~m}$ long crosses the first train in a time
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Total distance $=130+120=250 \mathrm{~m}$
Relative velocity $=30-(-20)=50 \mathrm{~m} / \mathrm{s}$
Hence $t=250 / 50=5 \mathrm{~s}$
Relative velocity $=30-(-20)=50 \mathrm{~m} / \mathrm{s}$
Hence $t=250 / 50=5 \mathrm{~s}$
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