A 2 kg stone tied at the end of a string 1 m long is whirled along a vertical circle at a constant speed of 4 m s - 1 . What will be the tension in the string (in newton) at the bottom-most point?

Question

A 2 kg stone tied at the end of a string 1 m long is whirled along a vertical circle at a constant speed of 4 m s - 1 . What will be the tension in the string (in newton) at the bottom-most point?,

MARKS App · Accepted Answer

Here, m = 2 k g , r = 1 m , v = 4 m s - 1 Tension at the bottom of the circle, T L = m g + m v 2 r = 2 0 + 2 × 4 2 1 = 52 N

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