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Question: Answered & Verified by Expert
A 20 cm long string, having a mass of 1.0 g, is fixed at both the ends. The tension in the string is 0.5 N. The string is set into vibrations using an external vibrator of frequency 100 Hz. Find the separation (in cm) between the successive nodes on the string.
PhysicsWaves and SoundNEET
Options:
  • A 5
  • B 3
  • C 2
  • D 1
Solution:
2918 Upvotes Verified Answer
The correct answer is: 5
l=20 cm; m=1 g; T=0.5 N; f=100 Hz

μ=1×10-320×10-2=12×10-2 

V=0.50.5×10-2=10 m s-1 m/s

λ=0.1 

λ2=0.05 m=5 cm 

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