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A $2.0 \mathrm{~cm}$ object is placed $15 \mathrm{~cm}$ in front of a concave mirror of focal length $10 \mathrm{~cm}$. What is the size and nature of the image?
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$4 \mathrm{~cm}$. real
$\frac{1}{\mathrm{v}}-\frac{1}{15}=\frac{1}{-10} \Rightarrow \mathrm{v}=-30 \mathrm{~cm}$
$m=\frac{-30}{-15}=2$, image size $=4 \mathrm{~cm}$
$m=\frac{-30}{-15}=2$, image size $=4 \mathrm{~cm}$
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