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A $20 \mathrm{~kg}$ block is initially at rest on a rough horizontal surface. A horizontal force of $75 \mathrm{~N}$ is required to set the block in motion. After it is in motion, a horizontal force of $60 \mathrm{~N}$ is required to keep the block moving with constant speed. The coefficient of static friction is
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0.38
Coefficient of friction
$\mu_s=\frac{F_l}{R}=\frac{75}{m g}=\frac{75}{20 \times 9.8}=0.38$
$\mu_s=\frac{F_l}{R}=\frac{75}{m g}=\frac{75}{20 \times 9.8}=0.38$
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