Search any question & find its solution
Question:
Answered & Verified by Expert
A $220 \mathrm{~V}$ AC supply is connected between points A and B (figure). What will be the potential difference $\mathrm{V}$ across the capacitor?
Options:
Solution:
1534 Upvotes
Verified Answer
The correct answer is:
$220 \sqrt{2} \mathrm{~V}$
$220 \sqrt{2} \mathrm{~V}$
As the given figure $\mathrm{p}-\mathrm{n}$ junction conducts during positive half cycyle only, then diode connected here will work is positive half cycle. Potential difference across $\mathrm{C}$ will be peak voltage when diode is in forword bias then the peak voltage of the given $\mathrm{AC}$ voltage
$$
=\mathrm{V}_0=\mathrm{V}_{\mathrm{rms}} \sqrt{2}=220 \sqrt{2} \mathrm{~V}
$$
$$
=\mathrm{V}_0=\mathrm{V}_{\mathrm{rms}} \sqrt{2}=220 \sqrt{2} \mathrm{~V}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.