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A $3.0 \mathrm{~cm}$ wire carrying a current of $10 \mathrm{~A}$ is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be $0.27 \mathrm{~T}$. What is the magnetic force on the wire?
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Verified Answer
Given, $\mathrm{d} \ell=3 \mathrm{~cm}=0.03 \mathrm{~m}, \mathrm{I}=10 \mathrm{~A}, \mathrm{~B}=0.27 \mathrm{~T}$, $\theta=90^{\circ} \Rightarrow \sin \theta=1, \mathrm{~F}=$ ?
$$
\begin{aligned}
\mathrm{F} &=\operatorname{Id} \ell \quad \mathrm{B} \sin \theta=10 \times 0.03 \times 0.27 \times 1 \\
&=8.1 \times 10^{-2} \mathrm{~N}
\end{aligned}
$$
The direction can be obtained by Fleming's left hand rule.
$$
\begin{aligned}
\mathrm{F} &=\operatorname{Id} \ell \quad \mathrm{B} \sin \theta=10 \times 0.03 \times 0.27 \times 1 \\
&=8.1 \times 10^{-2} \mathrm{~N}
\end{aligned}
$$
The direction can be obtained by Fleming's left hand rule.
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