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$A=\left[\begin{array}{ll}4 & 2 \\ 3 & 4\end{array}\right]$ then $|\operatorname{adj} A|$ is equal to
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The correct answer is:
$10$
$A=\left[\begin{array}{ll}4 & 2 \\ 3 & 4\end{array}\right]$
$\operatorname{adj} A=\left[\begin{array}{cc}4 & -2 \\ -3 & 4\end{array}\right]$
$|\operatorname{adj} A|=(4 \times 4)-(-3 \times-2)=16-6$
$|\operatorname{adj} A|=10$.
$\operatorname{adj} A=\left[\begin{array}{cc}4 & -2 \\ -3 & 4\end{array}\right]$
$|\operatorname{adj} A|=(4 \times 4)-(-3 \times-2)=16-6$
$|\operatorname{adj} A|=10$.
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