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$\int_{-a}^{4}\left(x^{8}-x^{4}+x^{2}+1\right) d x=2 \int_{0}^{4}\left(x^{8}-x^{4}+x^{2}+1\right) d x$ then $a=$
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4
If $\mathrm{f}(x)$ is an even function then
$\int_{-a}^{a} f(x) d x=2 \int_{0}^{a} f(x) d x$
Here $\mathrm{f}(x)=x^{8}-x^{4}+x^{2}+1$ is an even function, therefore $a=4$.
$\int_{-a}^{a} f(x) d x=2 \int_{0}^{a} f(x) d x$
Here $\mathrm{f}(x)=x^{8}-x^{4}+x^{2}+1$ is an even function, therefore $a=4$.
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