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A $5 A$ fuse wire can withstand a maximum power of $1 W$ in circuit. The resistance of the fuse wire is
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Verified Answer
The correct answer is:
$0.04 \Omega$
Power $P=i^2 R$
$\Rightarrow R=\frac{P}{i^2}$
Given, $P=1 \mathrm{~W}, i=5 \mathrm{~A}$
$\therefore R=\frac{1}{(5)^2}=0.04 \Omega$
$\Rightarrow R=\frac{P}{i^2}$
Given, $P=1 \mathrm{~W}, i=5 \mathrm{~A}$
$\therefore R=\frac{1}{(5)^2}=0.04 \Omega$
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