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Question: Answered & Verified by Expert
A 500 g ball is released from a height of m. Each time it makes contact with the ground it loses 25% of its energy. Find the KE it possesses after 3rd hit (take g=10 m s-2)
PhysicsCenter of Mass Momentum and CollisionNEET
Options:
  • A 15 J
  • B 11.25 J
  • C 8.44 J
  • D none of these
Solution:
2604 Upvotes Verified Answer
The correct answer is: 8.44 J
Kinetic energy after first hit, K1=e2K

34K=e2K

   e2=34 ( here e is coefficient of restitution ) 

Kinetic energy after third hit =e23K=2764mgh

=276412×10×4=27516=13516=8.44 J

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