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A $5.2$ molal aqueous solution of methyl alcohol, $\mathrm{CH}_3 \mathrm{OH}$, is supplied. What is the mole fraction of methyl alcohol in the solution?
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$0.086$
$0.086$
$\begin{aligned} \text { Molefraction of solute }\left(\mathrm{X}_2\right) \text { in aqueous solution } & =\frac{\mathrm{m}}{\mathrm{m}+\frac{1000}{18}} \\ & =\frac{5.2}{5.2+\frac{1000}{18}}=0.09\end{aligned}$
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