$6.5$ molal $\mathrm{KOH}=1000 \mathrm{gm}$ solvent has $6.5$ moles $\mathrm{KOH}$

so, wt. of solute $=6.5\times 56$

$=364 \mathrm{gm}$

wt. of solution $=1000+364=1364$

Volume of solution $=\frac{1364}{1.89} \mathrm{m}\ell$

Molarity $=\frac{\mathrm{mole} \mathrm{of} solute}{{\mathrm{V}}_{\mathrm{solution} } \mathrm{in} Litre}$

$=9.00$