Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A 60pF capacitor is fully charged by a 20V supply. It is then disconnected from the supply and is connected to another uncharged 60pF capacitor in parallel. The electrostatic energy that is lost in this process by the time the charge is redistributed between them is (in nJ ) ________
PhysicsCapacitanceJEE MainJEE Main 2020 (07 Jan Shift 2)
Solution:
1311 Upvotes Verified Answer
The correct answer is: 6

V0=20V
Heat loss =Ui-Ut
=12Cvo2-212CV022
=CVo24
=60×10-122024J
=6×10-9J=6 nJ

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.