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Question: Answered & Verified by Expert
A $700 \mathrm{pF}$ capacitor is charged by a $50 \mathrm{~V}$ battery. The electrostatic energy stored by it is
PhysicsCapacitanceJEE Main
Options:
  • A $17.0 \times 10^{-8} \mathrm{~J}$
  • B $13.6 \times 10^{-9} \mathrm{~J}$
  • C $9.5 \times 10^{-9} \mathrm{~J}$
  • D $8.7 \times 10^{-7} \mathrm{~J}$
Solution:
2842 Upvotes Verified Answer
The correct answer is: $8.7 \times 10^{-7} \mathrm{~J}$
$U=\frac{1}{2} C V^2=\frac{1}{2} \times 700 \times 10^{-12}(50)^2=8.7 \times 10^{-7} \mathrm{~J}$

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