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$\mathrm{A}$ and $\mathrm{B}$ are two interfering sources where $\mathrm{A}$ is ahead in phase by $54^{\circ}$ relative to $B$. The observation is taken from point $\mathrm{P}$ such that $\mathrm{PB}-\mathrm{PA}=2.5 \lambda$. Then the phase difference between the waves from $A$ and $B$ reaching point $\mathrm{P}$ is (in rad)
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$5.3 \pi$
$\begin{aligned} & \text { Total phase difference }=\phi_1+\phi_2 \\ & \begin{aligned} \phi_1 & =54 \times \frac{\pi}{180}=0.3 \pi \\ \phi_2 & =\frac{2 \pi}{\lambda} \times(\mathrm{PB}-\mathrm{PA}) \\ & =\frac{2 \pi}{\lambda} \times 2.5 \lambda=5 \pi \\ \therefore \quad & \phi_1+\phi_2=5 \pi+0.3 \pi=5.3 \pi\end{aligned}\end{aligned}$
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