Search any question & find its solution
Question:
Answered & Verified by Expert
A and $\mathrm{B}$ are two sets having 3 elements in common $\operatorname{lfn}(\mathrm{A})=5, \mathrm{n}(\mathrm{B})=4$, then what is $\mathrm{n}(\mathrm{A} \times \mathrm{B})$ equal to
Options:
Solution:
1065 Upvotes
Verified Answer
The correct answer is:
20
Here, $\mathrm{n}(\mathrm{A})=5$ and $\mathrm{n}(\mathrm{B})=$
$\cdot n(A \times B)=5 \times 4=20$
$[\because \mathrm{n}(\mathrm{A})=\mathrm{m}, \mathrm{n}(\mathrm{B})=\mathrm{n} \Rightarrow \mathrm{n}(\mathrm{A} \times \mathrm{B})=\mathrm{mn}]$
$\cdot n(A \times B)=5 \times 4=20$
$[\because \mathrm{n}(\mathrm{A})=\mathrm{m}, \mathrm{n}(\mathrm{B})=\mathrm{n} \Rightarrow \mathrm{n}(\mathrm{A} \times \mathrm{B})=\mathrm{mn}]$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.