$\vec{a}$ and $\vec{b}$ are two vectors such that $\vec{a}$ is not parallel to $\vec{b}$. If $\overrightarrow{\mathrm{p}}=(\mathrm{x}+2 \mathrm{y}+3) \overrightarrow{\mathrm{a}}+(5 \mathrm{x}-\mathrm{y}+2) \overrightarrow{\mathrm{b}}$ and $\overrightarrow{\mathrm{q}}=(2 \mathrm{x}+3 \mathrm{y}+5)$ $\vec{a}+(x-5 y-2) \vec{b}$ are two vectors such that $\vec{p}=2 \vec{q}$, then $\mathrm{x}-2 \mathrm{y}=$