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$A+B=\left[\begin{array}{ll}1 & 0 \\ 1 & 1\end{array}\right]$ and
$A-2 B=\left[\begin{array}{cc}-1 & 1 \\ 0 & -1\end{array}\right]$, then $A=$
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$A-2 B=\left[\begin{array}{cc}-1 & 1 \\ 0 & -1\end{array}\right]$, then $A=$
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Verified Answer
The correct answer is:
$\left[\begin{array}{ll}1 / 3 & 1 / 3 \\ 2 / 3 & 1 / 3\end{array}\right]$
$2 A+2 B=\left[\begin{array}{ll}2 & 0 \\ 2 & 2\end{array}\right]$,$A-2 B=\left[\begin{array}{cc}-1 & 1 \\ 0 & -1\end{array}\right]$
On adding, we get $3 A=\left[\begin{array}{ll}1 & 1 \\ 2 & 1\end{array}\right]$
$\Rightarrow A=\left[\begin{array}{ll}1 / 3 & 1 / 3 \\ 2 / 3 & 1 / 3\end{array}\right]$.
On adding, we get $3 A=\left[\begin{array}{ll}1 & 1 \\ 2 & 1\end{array}\right]$
$\Rightarrow A=\left[\begin{array}{ll}1 / 3 & 1 / 3 \\ 2 / 3 & 1 / 3\end{array}\right]$.
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