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Question: Answered & Verified by Expert
A, B, C and D are four particles with each of mass M lying on the vertices of a square of side a. They always move along a common circle with velocity v under mutual gravitational force. Find v so that they always remain on the vertices of the square 
PhysicsGravitationJEE Main
Options:
  • A GM22+122a
  • B GM2+12a
  • C GM22+1a
  • D none
Solution:
2006 Upvotes Verified Answer
The correct answer is: GM22+122a


From the above figure, it is clear that

Fnet=2F1+F3=MV2R        F1=F2

2 GM2a2+GM2a22=Mv2a/2

v=GM1+2222a

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