A + B = C + D . If initially the concentration of A a n d B are both equal but at equilibrium, concentration of D will be twice of that of A , then what will be the equilibrium constant of reaction?

Question

A + B = C + D . If initially the concentration of A a n d B are both equal but at equilibrium, concentration of D will be twice of that of A , then what will be the equilibrium constant of reaction?, 4 9, 9 4, 1 9, 4

MARKS App · Accepted Answer

Let the initial concentration be 'a' A + B → C + D Initial a a 0 0 at equilibrium a - x a - x x x given x = 2 a − x = 2 a − 2 x 3x = 2a x = 2 3 a at eq. ⇒ a 3 a 3 2 a 3 2 a 3 K eq = C D A B = 2 a 3 2a 3 a 3 a 3 = 4

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