Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
ABCD is a square with side 16 units and A is the origin. If the equation of the circle circumscribing the square ABCD is x2+y2=4k(x+y), then k=
MathematicsCircleAP EAMCETAP EAMCET 2018 (25 Apr Shift 1)
Options:
  • A 2
  • B 4
  • C 16
  • D 64
Solution:
2458 Upvotes Verified Answer
The correct answer is: 4

Clearly, AC is the diameter. So, equation of circle in diameter form is

x-0x-16+y-0y-16=0

x2-16x+y2-16y=0

x2+y2=16x+y

Comparing with the given equation, we get

k=4.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.