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Question: Answered & Verified by Expert
$A B$ is a variable chord of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$. If $A B$ subtends a right angle at the origin $O$, then $\frac{1}{OA^2}+\frac{1}{OB^2}$ equals to
MathematicsEllipseJEE Main
Options:
  • A $\frac{1}{a^2}+\frac{1}{b^2}$
  • B $\frac{1}{a^2}-\frac{1}{b^2}$
  • C $a^2+b^2$
  • D $a^2-b^2$
Solution:
2006 Upvotes Verified Answer
The correct answer is: $\frac{1}{a^2}+\frac{1}{b^2}$

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