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A bag contains 3 white, 2 blue and 5 red balls. One ball is drawn at random from this bag. Then, the probability that the ball drawn is not red is
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1948 Upvotes
Verified Answer
The correct answer is:
$1 / 2$
3 white, 2 blue, 5 red balls.
$$
P(\text { ball is not red })=\frac{3+2}{3+2+5}=\frac{1}{2}
$$
$$
P(\text { ball is not red })=\frac{3+2}{3+2+5}=\frac{1}{2}
$$
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