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A ball is dropped vertically from a height above the ground. It hits the ground and bounces up vertically to a height , Neglecting subsequent motion and air resistance, its velocity varies with height above the ground as
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The correct answer is:
(i) For uniformly accelerated/deaccelerated motion,
i.e., v - h graph will be a parabola (because the equation is quadratic).
(ii) Initially, velocity is downwards (-ve) and then after the collision it reverses its direction with lesser magnitude. i.e., velocity is upwards (+ve). Graph (a) satisfies both these conditions.
Note that time corresponds to the point on the graph where .

i.e., v - h graph will be a parabola (because the equation is quadratic).
(ii) Initially, velocity is downwards (-ve) and then after the collision it reverses its direction with lesser magnitude. i.e., velocity is upwards (+ve). Graph (a) satisfies both these conditions.
Note that time corresponds to the point on the graph where .

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