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Question: Answered & Verified by Expert
A ball is projected at an angle of 30° above with the horizontal from the top of a tower and strikes the ground in 5 s at an angle of 45° with the horizontal. Find the speed with which it was projected.
PhysicsMotion In Two DimensionsJEE Main
Options:
  • A 503-1 m s-1
  • B 502-1 m s-1
  • C 703-1 m s-1
  • D 803-1 m s-1
Solution:
2852 Upvotes Verified Answer
The correct answer is: 503-1 m s-1
vx = - vy



u cos 30° = - (u sin 30° - gt)

u32=-u2-10×5

u3+12=50

u=10013+1 u=503-1 m s-1
 

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