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Question: Answered & Verified by Expert
A ball of mass 0.15 kg hits the wall with its initial speed of 12 m s-1 and bounces back without changing its initial speed. If the force applied by the wall on the ball during the contact is 100 N. calculate the time duration of the contact of ball with the wall.
PhysicsCenter of Mass Momentum and CollisionJEE MainJEE Main 2022 (26 Jul Shift 2)
Options:
  • A 0.018 s
  • B 0.036 s
  • C 0.009 s
  • D 0.072 s
Solution:
2609 Upvotes Verified Answer
The correct answer is: 0.036 s

Given: m=1.5 kg & u=12 m s-1

Change in the momentum of the ball after the collision=2mv

=2×1.5×12

=36 N s

As the force applied during collision is equal to 100 N and if t is the duration of collision, so

100×t=Δp

t=36100 s

t=36×10-2 s=0.036 s

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