A ball of mass 0 . 5 kg moving horizontally at 10 m s - 1 strikes a vertical wall and rebounds with speed v . The magnitude of the change in linear momentum is found to be 8 . 0 kg m s - 1 . The magnitude of v is,

Question

A ball of mass 0 . 5 kg moving horizontally at 10 m s - 1 strikes a vertical wall and rebounds with speed v . The magnitude of the change in linear momentum is found to be 8 . 0 kg m s - 1 . The magnitude of v is,, 6 . 0 m s - 1, 9 . 0 m s - 1, 26 . 0 m s - 1, 13 . 0 m s - 1

MARKS App · Accepted Answer

Linear momentum is a vector quantity. Initial momentum = + m × 10 i ^ . Final momentum = - m v i ^ Change in linear momentum = - 10 m i ^ - m v i ^ = - 10 + v m i ^ Therefore, 10 + v × 0 . 5 = 8 ⇒ v = 16 - 10 = 6 m s - 1

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