Search any question & find its solution
Question:
Answered & Verified by Expert
A ball of mass 10 g moving with acceleration of $20 \mathrm{~m} / \mathrm{s}^2$ is hit by a force which acts on it for 0.1 sec . The impulsive force is
Options:
Solution:
2951 Upvotes
Verified Answer
The correct answer is:
0.3 Ns
Here: Mass of the ball $m=150 \mathrm{~g}$
$\begin{aligned}& \text {time }=0.15 \mathrm{~kg} \\& \text {Acceleration of the ball }=20 \mathrm{~m} / \mathrm{s}^2 \\& \mathrm{dt} = 0.1 \mathrm{~s}\end{aligned}$
Force, $\quad F=m a=0.15 \times 20=3 \mathrm{~N}$
Now impulsive force
$=F \times d t=3 \times 0.1=0.3 \mathrm{Ns}$
$\begin{aligned}& \text {time }=0.15 \mathrm{~kg} \\& \text {Acceleration of the ball }=20 \mathrm{~m} / \mathrm{s}^2 \\& \mathrm{dt} = 0.1 \mathrm{~s}\end{aligned}$
Force, $\quad F=m a=0.15 \times 20=3 \mathrm{~N}$
Now impulsive force
$=F \times d t=3 \times 0.1=0.3 \mathrm{Ns}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.