A ball of mass m = 0 . 5 kg is attached to the end of a string having length L = 0 . 5 m . The ball is rotated on a horizontal circular path about the vertical axis. The maximum tension that the string can bear is 324 N . The maximum possible value of the angular velocity of ball (in rad s - 1 ) is

Question

A ball of mass m = 0 . 5 kg is attached to the end of a string having length L = 0 . 5 m . The ball is rotated on a horizontal circular path about the vertical axis. The maximum tension that the string can bear is 324 N . The maximum possible value of the angular velocity of ball (in rad s - 1 ) is, 9, 18, 27, 36

MARKS App · Accepted Answer

T sin θ = m ω 2 r T sin θ = m ω 2 L sin θ ⇒ T = m ω 2 L ⇒ 3 2 4 = 1 2 ω 2 1 2 Therefore ω = 3 6 rad s - 1

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