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A ball of mass 'm' is attached to the free end of an inextensible string of length ' $\ell$ '.
Let 'T' be the tension in the string. The ball is moving in horizontal circular path
about the vertical axis. The angular velocity of the ball at any particular instant will
be
Options:
Let 'T' be the tension in the string. The ball is moving in horizontal circular path
about the vertical axis. The angular velocity of the ball at any particular instant will
be
Solution:
2273 Upvotes
Verified Answer
The correct answer is:
$\sqrt{\frac{\mathrm{T}}{\mathrm{m} \ell}}$
A ball of mass ' $m$ ' is attached to the free end of an inextensible string of length 'I'. Let 'T' be the tension in the string. The ball is moving in horizontal circular path about the vertical axis. The angular velocity of the ball at any particular instant will be $\sqrt{\frac{T}{m l}}$.
Explanation:
$$
\begin{array}{l}
\mathrm{T}=\mathrm{ml} \omega^{2} \\
\therefore \omega=\sqrt{\frac{T}{m l}}
\end{array}
$$
Explanation:
$$
\begin{array}{l}
\mathrm{T}=\mathrm{ml} \omega^{2} \\
\therefore \omega=\sqrt{\frac{T}{m l}}
\end{array}
$$
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