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A ball of mass $m$ is tied up with string and rotated along a horizontal circle of radius $r$. At an instant, its velocity is $v$, and tension in string is $T$, the force required for circular motion is
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The correct answer is:
$\frac{m v^2}{r}$
From figure,
$\therefore \quad T \sin \theta=\frac{m v^2}{r}$
$\therefore \quad T \sin \theta=\frac{m v^2}{r}$
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