Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A ball of radius r and density ρ falls freely under gravity through a distance h before entering water. Velocity of ball does not change even on entering water. If viscosity of water is η, the value of h is given by

PhysicsMechanical Properties of FluidsNEET
Options:
  • A 2 9 r 2 ( 1 - ρ η ) g
  • B 2 81 r 2 ( ρ - 1 η ) g
  • C 2 8 1 r 4 ( ρ - 1 η ) 2 g
  • D 2 9 r 4 ( ρ - 1 η ) 2 g
Solution:
2780 Upvotes Verified Answer
The correct answer is: 2 8 1 r 4 ( ρ - 1 η ) 2 g
Velocity of ball when the water surface 

v = 2 gh ............ i

Terminal velocity of ball inside the water 

v = 2 9 r 2 g ρ - 1 η ............ i i

Equating (i) and (ii)we get 2 gh = 2 9 r 2 g η ρ - 1 h = 2 8 1 r 4 ( ρ - 1 η ) 2 g

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.