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A ball $P$ is dropped vertically and another ball $Q$ is thrown horizontally with the same velocities from the same height and at the same time. If air resistance is neglected, then
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Verified Answer
The correct answer is:
Both reach the ground at the same time
Vertical component of velocities of both the balls are same and equal to zero.
So $t=\sqrt{\frac{2 h}{g}}$
\(\Rightarrow\) Both reach the ground at the same time
So $t=\sqrt{\frac{2 h}{g}}$
\(\Rightarrow\) Both reach the ground at the same time
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