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A balloon contains $2.27 \mathrm{~L}$ air and has a pressure of $1.013 \times 10^5 \mathrm{Nm}^{-2}$. The balloon rises to a certain height and expands to volume of $4540 \mathrm{~mL}$. What is the final pressure of air in balloon?
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The correct answer is:
$5.065 \times 10^4 \mathrm{Nm}^{-2}$
$\begin{aligned} & \mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2 \\ & 1.013 \times 10^5 \times 2.27=\mathrm{P}_2 \times 4.540 \\ & \mathrm{P}_2=5.065 \times 10^4 \mathrm{Nm}^{-2}\end{aligned}$
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