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Question: Answered & Verified by Expert
A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equilibrium state. The energy required to rotate it by 60o is W. Now, the torque required to keep the magnet in this new position is
PhysicsMagnetic Effects of CurrentNEETNEET 2016 (Phase 2)
Options:
  • A W3
  • B 3W
  • C 3W2
  • D 2W3
Solution:
1253 Upvotes Verified Answer
The correct answer is: 3W

W=PEcosθ1-cosθ2

W=PEcos0-cos60o

=PE2.

PE=2W

τ=PEsinθ=2Wsin60o=3W.

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